0,8=4t-5t^2

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Solution for 0,8=4t-5t^2 equation: 



0.8=4t-5t^2

We move all terms to the left:

0.8-(4t-5t^2)=0

We get rid of parentheses

5t^2-4t+0.8=0

a = 5; b = -4; c = +0.8;
Δ = b2-4ac
Δ = -42-4·5·0.8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{4}{10}=2/5$

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